2(x^2+1)=x

Solution for 2(x^2+1)=x equation:

Simplifying
2(x2 + 1) = x

Reorder the terms:
2(1 + x2) = x
(1 * 2 + x2 * 2) = x
(2 + 2x2) = x

Solving
2 + 2x2 = x

Solving for variable 'x'.

Reorder the terms:
2 + -1x + 2x2 = x + -1x

Combine like terms: x + -1x = 0
2 + -1x + 2x2 = 0

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
1 + -0.5x + x2 = 0

Move the constant term to the right:

Add '-1' to each side of the equation.
1 + -0.5x + -1 + x2 = 0 + -1

Reorder the terms:
1 + -1 + -0.5x + x2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -0.5x + x2 = 0 + -1
-0.5x + x2 = 0 + -1

Combine like terms: 0 + -1 = -1
-0.5x + x2 = -1

The x term is -0.5x.  Take half its coefficient (-0.25).
Square it (0.0625) and add it to both sides.

Add '0.0625' to each side of the equation.
-0.5x + 0.0625 + x2 = -1 + 0.0625

Reorder the terms:
0.0625 + -0.5x + x2 = -1 + 0.0625

Combine like terms: -1 + 0.0625 = -0.9375
0.0625 + -0.5x + x2 = -0.9375

Factor a perfect square on the left side:
(x + -0.25)(x + -0.25) = -0.9375

Can't calculate square root of the right side.

The solution to this equation could not be determined.